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Topic: how many amps for a 1.5kw heater? ( Topic Closed)
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14/3/2012 at 8:50pm
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Hi
Ive just brought a oil filled radiator not massove but 1.5 kw with 3 settings how many amps would this use? I was thinking about 7 top heat!! Would only use prob 2nd heat setting
thanks
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14/3/2012 at 9:31pm
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W/V=A 1500/240=7 max
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14/3/2012 at 9:44pm
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This should help.
Griff
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14/3/2012 at 9:44pm
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6.521739130434783 amps to be precise
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15/3/2012 at 10:39am
Location: New Milton Hants Outfit: Compass Magnum Classic 540 (now sold)
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Every post is correct, just basic "Ohms law" however, what no one has pointed out is that your heater is probably fitted with a "rheostat" control (the dial with the numbers on).
When the heater is running, it runs at its maximum 1500watts.
The rheostat simply works like a timer, switching the power on and then off according to whatever number it is set to.
The lower the setting number, the longer the power is off.
You can usually hear the rheostat clicking as it switches on and off every few minutes.
A thermostat control works more or less the same way but this time it is controlled by temperature.
Vin Blanc
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15/3/2012 at 1:58pm
Location: Northern Ireland Outfit: Sterckeman Alize Concept CP480
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Quote: Originally posted by Bob61 on 14/3/2012
6.521739130434783 amps to be precise 
Not sure what system you're using ... but my maths tell me that 1500/240 = 6.25 ... precisely
However ... as voltage is seldom delivered at exactly 240 ... hence the oft quoted 220-240 range ... you'd get 6.8181818181 etc at 220.
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15/3/2012 at 2:16pm
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For the same heater you will get less amps at 220 volts than 240 volts,
240 volts 1500W, 6.25A, same heater at 220 volts 5.729166666
Saxo1
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15/3/2012 at 2:50pm
Location: Northern Ireland Outfit: Sterckeman Alize Concept CP480
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Sorry Saxo .... but if Ohm's Law is correct ... then if you decrease the voltage, you increase the ampage.
1500/220 has to be more than 1500/240
6.818181 as opposed to 6.25
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15/3/2012 at 5:20pm
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If you pass a given voltage through a given resistance you will get a given amps i.e.
1 volt through 1ohm = 1 amp
10 volts through 1 ohm =10 amps
The resistance of the heater is constant,a 1500 watt 230v rated heater has a resistance of 35.266666666 ohms, using the formula:
I=V/R 230volts divided by 35.266666666 = 6.5217392 amps
I=V/R 240 volts divided by 35.266666666= 6.8052931 amps
I=V/R 220 volts divided by 35.266666666 =6.2381852 amps
Using P=VI at 230 v the power is 1500watts ,at 240v the power is 1565 watts ,at 220v the power is 1434 watts.
That is why the spec plate sometimes gives a voltage range of 220v to 240v /1850 to 2200 watts.
Not that this is of any relevance to the OP
Saxo1
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15/3/2012 at 5:54pm
Location: Wiltshire Outfit: Outwell Nevada M
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The heater load won't be purely resistive - most likely inductive as well as capacitive, so it's not correct to calculate resistance to 9 decimal places.
I don't think we can know what is the input power of the heater at different voltages as it depends on the characteristics of the heater internal power supply (is it constant current or constant voltage being delivered to the heater element), or neither perhaps as it's probably simple AC?
For the benefit of the OP and to keep things simple, I would calculate at nominal voltage 230V with the nominal power stated on the spec plate (1500W?) and add 10% for safety margin.
So it's 7.2A 
------------- Pete B
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15/3/2012 at 7:04pm
Location: Worcestershire Outfit: Defender 90 and MyWay Voyager Raid
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Not forgetting any voltage drop anywhere, whether it is between the site distribution board and the EHU post or in your EHU cable.
I've seen voltages as low as 180v......
------------- Love a lot. Trust a few. But ALWAYS paddle your own canoe!!
Minds are like parachutes:- They only function when they are open!!!
Those who talk don't know.
Those who know don't talk.
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15/3/2012 at 9:51pm
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Quote: Originally posted by Kelper on 15/3/2012
Quote: Originally posted by Bob61 on 14/3/2012
6.521739130434783 amps to be precise 
Not sure what system you're using ... but my maths tell me that 1500/240 = 6.25 ... precisely
However ... as voltage is seldom delivered at exactly 240 ... hence the oft quoted 220-240 range ... you'd get 6.8181818181 etc at 220.
Now look what you've started!!
The oft quoted range for the UK is, as you say, 220-240v. Being an average sort of Joe Soap I, like lots of other average Joe Soaps, take that as a 230v average.
1500 watts divided by 230 volts = 6.521739130434783 amps (according to my highly accurate computer calculator provided by Microsoft. 
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16/3/2012 at 2:18am
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Quote: Originally posted by Vin Blanc on 15/3/2012
Ohms law states that for a given wattage, the current (amps) will rise as the voltage drops.
This is not Ohm's law. Ohm's law equates current, resistance and voltage: V = IR.
The equation you are referring to is P = VI. Current would have to decrease when voltage increased in order to produce the same power. But then I think you are interpreting the power rating of an appliance as meaning it has a constant power output, which is not the case.
The power rating is for a quoted voltage, usually 230V. If the voltage was higher, the current would be higher and the power consumption higher. It's the resistance that's the constant, not power.
------------- Richard
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16/3/2012 at 8:44am
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Sanhozay is right.
Ohms Law relates voltage, current, and resistance.
Ohm's Law says I = V/R where 'I' is current in Amps, 'V' is Volts, and 'R' is the resistance of the conductor in Ohms.
If you know any two of the constants, you can calculate the other one: for instance, to find the voltage if you know the resistance in Ohms and the current in Amps the equation becomes V = I (x) R and so on
BUT ...
Back to the OP:
Quote: Originally posted by Lisamitt on 14/3/2012...a oil filled radiator not massive but 1.5 kw with 3 settings how many amps would this use?
A rough rule of thumb will suffice here - there is no need to bring Ohm's Law into play (especially as doing so seems to have given this thread an ill-humoured combative tone).
We know that the OP's appliance is rated 1.5KW (1,500 Watts). We can assume a supply voltage of approx 230V (average of the range 220V - 240V).
Our very approximate rule of thumb is that 1,000 Watts (one kilowatt) is, very roughly, 4.5 (four-and-a-half) Amps (that is why a 3KW electric bar heater is the limit on a domestic ring main). So the OP's oil-filled radiator will draw - and I repeat it is only a rough estimate - about 6-7 Amps.
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16/3/2012 at 8:48am
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Quote: Originally posted by sanhozay on 16/3/2012Quote: Originally posted by Vin Blanc on 15/3/2012Ohms law states that for a given wattage, the current (amps) will rise as the voltage drops. This is not Ohm's law. Ohm's law equates current, resistance and voltage: V = IR.
The equation you are referring to is P = VI. Current would have to decrease when voltage increased in order to produce the same power. But then I think you are interpreting the power rating of an appliance as meaning it has a constant power output, which is not the case.
The power rating is for a quoted voltage, usually 230V. If the voltage was higher, the current would be higher and the power consumption higher. It's the resistance that's the constant, not power.
Nonsense. Current does not get higher as the voltage increases, it decreases!! Why do people insist on spreading misinformation?
------------- Ploppy son of Ploppy.
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